Ex 2.1, 1 - Chapter 2 Class 12 Inverse Trigonometric Functions

Last updated at August 20, 2026 by

Ex 2.1, 1 - Find principal valueΒ of sin-1 (-1/2) - Chapter 2 - Ex 2.1

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Ex 2.1, 1 Find the principal value of sin-1 (βˆ’1/2) Let y = sin-1 ((βˆ’1)/2) y = βˆ’ sin-1 (1/2) y = βˆ’ 𝛑/πŸ” Since Range of sin βˆ’1 is [(βˆ’π…)/𝟐, ( 𝝅)/𝟐] Hence, Principal Value is (βˆ’π…)/πŸ” We know that sinβˆ’1 (βˆ’x) = βˆ’ sin βˆ’1 x Since sin πœ‹/6 = 1/2 πœ‹/6 = sinβˆ’1 (𝟏/𝟐)

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